Base | Representation |
---|---|
bin | 10000000011110010000100… |
… | …01010011000000100101011 |
3 | 11122001000110110021102222012 |
4 | 20001321002022120010223 |
5 | 14112042222231432021 |
6 | 203035102454350135 |
7 | 10303243021541462 |
oct | 1001710212300453 |
9 | 148030413242865 |
10 | 35314331124011 |
11 | 102857a6305455 |
12 | 3b641a205b34b |
13 | 1692186418544 |
14 | 8a13193039d9 |
15 | 413917de835b |
hex | 201e4229812b |
35314331124011 has 2 divisors, whose sum is σ = 35314331124012. Its totient is φ = 35314331124010.
The previous prime is 35314331124001. The next prime is 35314331124073. The reversal of 35314331124011 is 11042113341353.
It is a weak prime.
It is an emirp because it is prime and its reverse (11042113341353) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-35314331124011 is a prime.
It is not a weakly prime, because it can be changed into another prime (35314331124001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17657165562005 + 17657165562006.
It is an arithmetic number, because the mean of its divisors is an integer number (17657165562006).
Almost surely, 235314331124011 is an apocalyptic number.
35314331124011 is a deficient number, since it is larger than the sum of its proper divisors (1).
35314331124011 is an equidigital number, since it uses as much as digits as its factorization.
35314331124011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 32.
Adding to 35314331124011 its reverse (11042113341353), we get a palindrome (46356444465364).
The spelling of 35314331124011 in words is "thirty-five trillion, three hundred fourteen billion, three hundred thirty-one million, one hundred twenty-four thousand, eleven".
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