Base | Representation |
---|---|
bin | 1010010001110010001… |
… | …11010101001011101001 |
3 | 1020202112022122020220120 |
4 | 11020321013111023221 |
5 | 21241220224310403 |
6 | 430122142313453 |
7 | 34341163400523 |
oct | 5107107251351 |
9 | 1222468566816 |
10 | 353145541353 |
11 | 12684a4a7100 |
12 | 58537888889 |
13 | 273bc4804b7 |
14 | 13141522a13 |
15 | 92bd295e53 |
hex | 52391d52e9 |
353145541353 has 12 divisors (see below), whose sum is σ = 517557653424. Its totient is φ = 214027600600.
The previous prime is 353145541351. The next prime is 353145541373.
353145541353 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 353145541353 - 21 = 353145541351 is a prime.
It is not an unprimeable number, because it can be changed into a prime (353145541351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 486426003 + ... + 486426728.
It is an arithmetic number, because the mean of its divisors is an integer number (43129804452).
Almost surely, 2353145541353 is an apocalyptic number.
353145541353 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
It is an amenable number.
353145541353 is a deficient number, since it is larger than the sum of its proper divisors (164412112071).
353145541353 is a wasteful number, since it uses less digits than its factorization.
353145541353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 972852756 (or 972852745 counting only the distinct ones).
The product of its digits is 810000, while the sum is 42.
It can be divided in two parts, 353145 and 541353, that added together give a palindrome (894498).
The spelling of 353145541353 in words is "three hundred fifty-three billion, one hundred forty-five million, five hundred forty-one thousand, three hundred fifty-three".
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