Base | Representation |
---|---|
bin | 101000001011100100100101… |
… | …1010000100111010011110001 |
3 | 1201100101222020121102221212210 |
4 | 1100113021023100213103301 |
5 | 332311131040041344403 |
6 | 3251405221030042333 |
7 | 134305526002605621 |
oct | 12027111320472361 |
9 | 1640358217387783 |
10 | 353434121434353 |
11 | a26846295a5303 |
12 | 33781a981a93a9 |
13 | 1222990518955b |
14 | 633c434a68881 |
15 | 2acd974e95b03 |
hex | 141724b4274f1 |
353434121434353 has 4 divisors (see below), whose sum is σ = 471245495245808. Its totient is φ = 235622747622900.
The previous prime is 353434121434327. The next prime is 353434121434391.
353434121434353 is nontrivially palindromic in base 10.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 353434121434353 - 222 = 353434117240049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (353434121430353) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 58905686905723 + ... + 58905686905728.
It is an arithmetic number, because the mean of its divisors is an integer number (117811373811452).
Almost surely, 2353434121434353 is an apocalyptic number.
It is an amenable number.
353434121434353 is a deficient number, since it is larger than the sum of its proper divisors (117811373811455).
353434121434353 is a wasteful number, since it uses less digits than its factorization.
353434121434353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 117811373811454.
The product of its digits is 9331200, while the sum is 48.
The spelling of 353434121434353 in words is "three hundred fifty-three trillion, four hundred thirty-four billion, one hundred twenty-one million, four hundred thirty-four thousand, three hundred fifty-three".
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