Base | Representation |
---|---|
bin | 101000001011100111100000… |
… | …1100101001111010111111011 |
3 | 1201100102120110021112101000001 |
4 | 1100113033001211033113323 |
5 | 332311231420242120443 |
6 | 3251412140130053431 |
7 | 134306140430502601 |
oct | 12027170145172773 |
9 | 1640376407471001 |
10 | 353440401520123 |
11 | a2687261538735 |
12 | 3378314b41a277 |
13 | 1222a39629ca38 |
14 | 633c86cb45871 |
15 | 2acdbe14a6d4d |
hex | 14173c194f5fb |
353440401520123 has 2 divisors, whose sum is σ = 353440401520124. Its totient is φ = 353440401520122.
The previous prime is 353440401520103. The next prime is 353440401520127. The reversal of 353440401520123 is 321025104044353.
It is a strong prime.
It is an emirp because it is prime and its reverse (321025104044353) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-353440401520123 is a prime.
It is not a weakly prime, because it can be changed into another prime (353440401520127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 176720200760061 + 176720200760062.
It is an arithmetic number, because the mean of its divisors is an integer number (176720200760062).
Almost surely, 2353440401520123 is an apocalyptic number.
353440401520123 is a deficient number, since it is larger than the sum of its proper divisors (1).
353440401520123 is an equidigital number, since it uses as much as digits as its factorization.
353440401520123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 172800, while the sum is 37.
Adding to 353440401520123 its reverse (321025104044353), we get a palindrome (674465505564476).
The spelling of 353440401520123 in words is "three hundred fifty-three trillion, four hundred forty billion, four hundred one million, five hundred twenty thousand, one hundred twenty-three".
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