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3538200480457 is a prime number
BaseRepresentation
bin110011011111001101001…
…011101100101011001001
3110112020201021102110110011
4303133031023230223021
5430432213310333312
611305232111351521
7513424622600536
oct63371513545311
913466637373404
103538200480457
1111445a6a26585
124918882225a1
131c885cc7aa66
14c336d6d7d8d
1562083d9cda7
hex337cd2ecac9

3538200480457 has 2 divisors, whose sum is σ = 3538200480458. Its totient is φ = 3538200480456.

The previous prime is 3538200480389. The next prime is 3538200480487. The reversal of 3538200480457 is 7540840028353.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2339725107456 + 1198475373001 = 1529616^2 + 1094749^2 .

It is a cyclic number.

It is not a de Polignac number, because 3538200480457 - 223 = 3538192091849 is a prime.

It is a super-3 number, since 3×35382004804573 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 3538200480457.

It is not a weakly prime, because it can be changed into another prime (3538200480487) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1769100240228 + 1769100240229.

It is an arithmetic number, because the mean of its divisors is an integer number (1769100240229).

Almost surely, 23538200480457 is an apocalyptic number.

It is an amenable number.

3538200480457 is a deficient number, since it is larger than the sum of its proper divisors (1).

3538200480457 is an equidigital number, since it uses as much as digits as its factorization.

3538200480457 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3225600, while the sum is 49.

The spelling of 3538200480457 in words is "three trillion, five hundred thirty-eight billion, two hundred million, four hundred eighty thousand, four hundred fifty-seven".