Base | Representation |
---|---|
bin | 10000000110010001111001… |
… | …11111111010110111101001 |
3 | 11122100012221220001020002222 |
4 | 20003020330333322313221 |
5 | 14114443443310432133 |
6 | 203142333535003425 |
7 | 10312401364606202 |
oct | 1003107477726751 |
9 | 148305856036088 |
10 | 35400143842793 |
11 | 10309131357154 |
12 | 3b78950669575 |
13 | 169a2b0896012 |
14 | 8a553a05a5a9 |
15 | 415c8b858e98 |
hex | 20323cffade9 |
35400143842793 has 2 divisors, whose sum is σ = 35400143842794. Its totient is φ = 35400143842792.
The previous prime is 35400143842697. The next prime is 35400143842799. The reversal of 35400143842793 is 39724834100453.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 26201376337984 + 9198767504809 = 5118728^2 + 3032947^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-35400143842793 is a prime.
It is not a weakly prime, because it can be changed into another prime (35400143842799) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17700071921396 + 17700071921397.
It is an arithmetic number, because the mean of its divisors is an integer number (17700071921397).
Almost surely, 235400143842793 is an apocalyptic number.
It is an amenable number.
35400143842793 is a deficient number, since it is larger than the sum of its proper divisors (1).
35400143842793 is an equidigital number, since it uses as much as digits as its factorization.
35400143842793 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8709120, while the sum is 53.
The spelling of 35400143842793 in words is "thirty-five trillion, four hundred billion, one hundred forty-three million, eight hundred forty-two thousand, seven hundred ninety-three".
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