Base | Representation |
---|---|
bin | 1010010011011001100… |
… | …10010101001001010011 |
3 | 1020211202201212211221111 |
4 | 11021230302111021103 |
5 | 21300004141421121 |
6 | 430344151234151 |
7 | 34401521121223 |
oct | 5115462251123 |
9 | 1224681784844 |
10 | 354012451411 |
11 | 1271548884a3 |
12 | 5873a078957 |
13 | 274c9c5c628 |
14 | 131c4708083 |
15 | 931e4382e1 |
hex | 526cc95253 |
354012451411 has 2 divisors, whose sum is σ = 354012451412. Its totient is φ = 354012451410.
The previous prime is 354012451379. The next prime is 354012451417. The reversal of 354012451411 is 114154210453.
It is a strong prime.
It is an emirp because it is prime and its reverse (114154210453) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 354012451411 - 25 = 354012451379 is a prime.
It is not a weakly prime, because it can be changed into another prime (354012451417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177006225705 + 177006225706.
It is an arithmetic number, because the mean of its divisors is an integer number (177006225706).
Almost surely, 2354012451411 is an apocalyptic number.
354012451411 is a deficient number, since it is larger than the sum of its proper divisors (1).
354012451411 is an equidigital number, since it uses as much as digits as its factorization.
354012451411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 354012451411 its reverse (114154210453), we get a palindrome (468166661864).
The spelling of 354012451411 in words is "three hundred fifty-four billion, twelve million, four hundred fifty-one thousand, four hundred eleven".
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