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354012451411 is a prime number
BaseRepresentation
bin1010010011011001100…
…10010101001001010011
31020211202201212211221111
411021230302111021103
521300004141421121
6430344151234151
734401521121223
oct5115462251123
91224681784844
10354012451411
111271548884a3
125873a078957
13274c9c5c628
14131c4708083
15931e4382e1
hex526cc95253

354012451411 has 2 divisors, whose sum is σ = 354012451412. Its totient is φ = 354012451410.

The previous prime is 354012451379. The next prime is 354012451417. The reversal of 354012451411 is 114154210453.

It is a strong prime.

It is an emirp because it is prime and its reverse (114154210453) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 354012451411 - 25 = 354012451379 is a prime.

It is not a weakly prime, because it can be changed into another prime (354012451417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177006225705 + 177006225706.

It is an arithmetic number, because the mean of its divisors is an integer number (177006225706).

Almost surely, 2354012451411 is an apocalyptic number.

354012451411 is a deficient number, since it is larger than the sum of its proper divisors (1).

354012451411 is an equidigital number, since it uses as much as digits as its factorization.

354012451411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 354012451411 its reverse (114154210453), we get a palindrome (468166661864).

The spelling of 354012451411 in words is "three hundred fifty-four billion, twelve million, four hundred fifty-one thousand, four hundred eleven".