Base | Representation |
---|---|
bin | 1010010011011001101… |
… | …00001100110101010011 |
3 | 1020211202202210202102112 |
4 | 11021230310030311103 |
5 | 21300004303113101 |
6 | 430344205535535 |
7 | 34401525232415 |
oct | 5115464146523 |
9 | 1224682722375 |
10 | 354012941651 |
11 | 127155092856 |
12 | 5873a2745ab |
13 | 274ca0a1805 |
14 | 131c47d49b5 |
15 | 931e4d36bb |
hex | 526cd0cd53 |
354012941651 has 2 divisors, whose sum is σ = 354012941652. Its totient is φ = 354012941650.
The previous prime is 354012941603. The next prime is 354012941663. The reversal of 354012941651 is 156149210453.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 354012941651 - 214 = 354012925267 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 354012941599 and 354012941608.
It is not a weakly prime, because it can be changed into another prime (354012949651) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177006470825 + 177006470826.
It is an arithmetic number, because the mean of its divisors is an integer number (177006470826).
Almost surely, 2354012941651 is an apocalyptic number.
354012941651 is a deficient number, since it is larger than the sum of its proper divisors (1).
354012941651 is an equidigital number, since it uses as much as digits as its factorization.
354012941651 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 129600, while the sum is 41.
The spelling of 354012941651 in words is "three hundred fifty-four billion, twelve million, nine hundred forty-one thousand, six hundred fifty-one".
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