Base | Representation |
---|---|
bin | 110011100001010000100… |
… | …010000000101111101011 |
3 | 110112110101212000020002022 |
4 | 303201100202000233223 |
5 | 431001221430121011 |
6 | 11310234511455055 |
7 | 513533341462100 |
oct | 63412042005753 |
9 | 13473355006068 |
10 | 3540404145131 |
11 | 1145527929457 |
12 | 4921a222748b |
13 | 1c8b21693459 |
14 | c34dc24aaa7 |
15 | 621625908db |
hex | 33850880beb |
3540404145131 has 12 divisors (see below), whose sum is σ = 4127248244808. Its totient is φ = 3028133963232.
The previous prime is 3540404145121. The next prime is 3540404145191. The reversal of 3540404145131 is 1315414040453.
It is not a de Polignac number, because 3540404145131 - 26 = 3540404145067 is a prime.
It is a super-2 number, since 2×35404041451312 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 3540404145091 and 3540404145100.
It is not an unprimeable number, because it can be changed into a prime (3540404145101) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 77335946 + ... + 77381711.
It is an arithmetic number, because the mean of its divisors is an integer number (343937353734).
Almost surely, 23540404145131 is an apocalyptic number.
3540404145131 is a deficient number, since it is larger than the sum of its proper divisors (586844099677).
3540404145131 is a wasteful number, since it uses less digits than its factorization.
3540404145131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 154718138 (or 154718131 counting only the distinct ones).
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 3540404145131 its reverse (1315414040453), we get a palindrome (4855818185584).
The spelling of 3540404145131 in words is "three trillion, five hundred forty billion, four hundred four million, one hundred forty-five thousand, one hundred thirty-one".
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