3540712607673 has 4 divisors (see below), whose sum is σ = 4720950143568. Its totient is φ = 2360475071780.

The previous prime is 3540712607633. The next prime is 3540712607693. The reversal of 3540712607673 is 3767062170453.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3540712607673 - 2¹² = 3540712603577 is a prime.

It is not an unprimeable number, because it can be changed into a prime (3540712607633) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 590118767943 + ... + 590118767948.

It is an arithmetic number, because the mean of its divisors is an integer number (1180237535892).

Almost surely, 2^{3540712607673} is an apocalyptic number.

It is an amenable number.

3540712607673 is a deficient number, since it is larger than the sum of its proper divisors (1180237535895).

3540712607673 is a wasteful number, since it uses less digits than its factorization.

3540712607673 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1180237535894.

The product of its (nonzero) digits is 4445280, while the sum is 51.

The spelling of 3540712607673 in words is "three trillion, five hundred forty billion, seven hundred twelve million, six hundred seven thousand, six hundred seventy-three".