Base | Representation |
---|---|
bin | 110011100010111100110… |
… | …001110101010101000011 |
3 | 110112122002102021222221001 |
4 | 303202330301311111003 |
5 | 431013431334411003 |
6 | 11311135024512431 |
7 | 513626343120025 |
oct | 63427461652503 |
9 | 13478072258831 |
10 | 3542220232003 |
11 | 1146279a803a2 |
12 | 49260a47b717 |
13 | 1c90509c677b |
14 | c3631510015 |
15 | 6221bc2561d |
hex | 338bcc75543 |
3542220232003 has 2 divisors, whose sum is σ = 3542220232004. Its totient is φ = 3542220232002.
The previous prime is 3542220231943. The next prime is 3542220232007. The reversal of 3542220232003 is 3002320222453.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3542220232003 - 225 = 3542186677571 is a prime.
It is a super-3 number, since 3×35422202320033 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (3542220232007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1771110116001 + 1771110116002.
It is an arithmetic number, because the mean of its divisors is an integer number (1771110116002).
Almost surely, 23542220232003 is an apocalyptic number.
3542220232003 is a deficient number, since it is larger than the sum of its proper divisors (1).
3542220232003 is an equidigital number, since it uses as much as digits as its factorization.
3542220232003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 28.
Adding to 3542220232003 its reverse (3002320222453), we get a palindrome (6544540454456).
The spelling of 3542220232003 in words is "three trillion, five hundred forty-two billion, two hundred twenty million, two hundred thirty-two thousand, three".
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