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3542405340361 is a prime number
BaseRepresentation
bin110011100011000111110…
…011111101110011001001
3110112122120022121110212011
4303203013303331303021
5431014321231342421
611311205240215521
7513634051402366
oct63430763756311
913478508543764
103542405340361
111146364512008
1249266046a5a1
131c9080168844
14c364bd3746d
156222d0dc4e1
hex338c7cfdcc9

3542405340361 has 2 divisors, whose sum is σ = 3542405340362. Its totient is φ = 3542405340360.

The previous prime is 3542405340211. The next prime is 3542405340389. The reversal of 3542405340361 is 1630435042453.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3062433500361 + 479971840000 = 1749981^2 + 692800^2 .

It is a cyclic number.

It is not a de Polignac number, because 3542405340361 - 239 = 2992649526473 is a prime.

It is a super-3 number, since 3×35424053403613 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (3542405380361) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1771202670180 + 1771202670181.

It is an arithmetic number, because the mean of its divisors is an integer number (1771202670181).

Almost surely, 23542405340361 is an apocalyptic number.

It is an amenable number.

3542405340361 is a deficient number, since it is larger than the sum of its proper divisors (1).

3542405340361 is an equidigital number, since it uses as much as digits as its factorization.

3542405340361 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 518400, while the sum is 40.

The spelling of 3542405340361 in words is "three trillion, five hundred forty-two billion, four hundred five million, three hundred forty thousand, three hundred sixty-one".