Base | Representation |
---|---|
bin | 110011100011001000111… |
… | …100000100100011101011 |
3 | 110112122121122011210121002 |
4 | 303203020330010203223 |
5 | 431014341101224121 |
6 | 11311211153305215 |
7 | 513634401146405 |
oct | 63431074044353 |
9 | 13478548153532 |
10 | 3542424242411 |
11 | 114637415243a |
12 | 49266686520b |
13 | 1c90840562a2 |
14 | c3650657b75 |
15 | 6222eac2e0b |
hex | 338c8f048eb |
3542424242411 has 2 divisors, whose sum is σ = 3542424242412. Its totient is φ = 3542424242410.
The previous prime is 3542424242381. The next prime is 3542424242437. The reversal of 3542424242411 is 1142424242453.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3542424242411 - 214 = 3542424226027 is a prime.
It is a super-3 number, since 3×35424242424113 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (3542424242011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1771212121205 + 1771212121206.
It is an arithmetic number, because the mean of its divisors is an integer number (1771212121206).
Almost surely, 23542424242411 is an apocalyptic number.
3542424242411 is a deficient number, since it is larger than the sum of its proper divisors (1).
3542424242411 is an equidigital number, since it uses as much as digits as its factorization.
3542424242411 is an evil number, because the sum of its binary digits is even.
The product of its digits is 245760, while the sum is 38.
Adding to 3542424242411 its reverse (1142424242453), we get a palindrome (4684848484864).
The spelling of 3542424242411 in words is "three trillion, five hundred forty-two billion, four hundred twenty-four million, two hundred forty-two thousand, four hundred eleven".
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