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354242517053363 is a prime number
BaseRepresentation
bin101000010001011101000001…
…1011001001010111110110011
31201110021020212002102100000122
41100202322003121022332303
5332412402133331201423
63253224433221440455
7134421114543155201
oct12042720331127663
91643236762370018
10354242517053363
11a296645387a904
12338926a627012b
1312287c06615513
14636960203c071
152ae49da37d8c8
hex1422e8364afb3

354242517053363 has 2 divisors, whose sum is σ = 354242517053364. Its totient is φ = 354242517053362.

The previous prime is 354242517053309. The next prime is 354242517053377. The reversal of 354242517053363 is 363350715242453.

It is a strong prime.

It is an emirp because it is prime and its reverse (363350715242453) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-354242517053363 is a prime.

It is a super-3 number, since 3×3542425170533633 (a number of 45 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (354248517053363) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177121258526681 + 177121258526682.

It is an arithmetic number, because the mean of its divisors is an integer number (177121258526682).

Almost surely, 2354242517053363 is an apocalyptic number.

354242517053363 is a deficient number, since it is larger than the sum of its proper divisors (1).

354242517053363 is an equidigital number, since it uses as much as digits as its factorization.

354242517053363 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27216000, while the sum is 53.

The spelling of 354242517053363 in words is "three hundred fifty-four trillion, two hundred forty-two billion, five hundred seventeen million, fifty-three thousand, three hundred sixty-three".