Base | Representation |
---|---|
bin | 1010010100000000000… |
… | …01001101000101001001 |
3 | 1020212121020000222210121 |
4 | 11022000001031011021 |
5 | 21301134242231031 |
6 | 430440155143241 |
7 | 34412516543131 |
oct | 5120001150511 |
9 | 1225536028717 |
10 | 354335117641 |
11 | 1272aaa333aa |
12 | 5880a144b21 |
13 | 2754ba652ab |
14 | 132154dbac1 |
15 | 933c923011 |
hex | 528004d149 |
354335117641 has 2 divisors, whose sum is σ = 354335117642. Its totient is φ = 354335117640.
The previous prime is 354335117627. The next prime is 354335117651. The reversal of 354335117641 is 146711533453.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 195629290000 + 158705827641 = 442300^2 + 398379^2 .
It is an emirp because it is prime and its reverse (146711533453) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 354335117641 - 213 = 354335109449 is a prime.
It is a super-3 number, since 3×3543351176413 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (354335117611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177167558820 + 177167558821.
It is an arithmetic number, because the mean of its divisors is an integer number (177167558821).
Almost surely, 2354335117641 is an apocalyptic number.
It is an amenable number.
354335117641 is a deficient number, since it is larger than the sum of its proper divisors (1).
354335117641 is an equidigital number, since it uses as much as digits as its factorization.
354335117641 is an evil number, because the sum of its binary digits is even.
The product of its digits is 453600, while the sum is 43.
The spelling of 354335117641 in words is "three hundred fifty-four billion, three hundred thirty-five million, one hundred seventeen thousand, six hundred forty-one".
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