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354500023197049 is a prime number
BaseRepresentation
bin101000010011010100111011…
…1111101001001110101111001
31201111011212112010122210112121
41100212221313331021311321
5332431112021414301144
63253543021252041241
7134445532022236612
oct12046516775116571
91644155463583477
10354500023197049
11a2a55685330994
1233914590603221
13122a6293803942
146377c6d6c0c09
152aeb55c140384
hex1426a77f49d79

354500023197049 has 2 divisors, whose sum is σ = 354500023197050. Its totient is φ = 354500023197048.

The previous prime is 354500023197043. The next prime is 354500023197059. The reversal of 354500023197049 is 940791320005453.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 354254245219449 + 245777977600 = 18821643^2 + 495760^2 .

It is a cyclic number.

It is not a de Polignac number, because 354500023197049 - 215 = 354500023164281 is a prime.

It is a super-3 number, since 3×3545000231970493 (a number of 45 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 354500023196987 and 354500023197005.

It is not a weakly prime, because it can be changed into another prime (354500023197043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177250011598524 + 177250011598525.

It is an arithmetic number, because the mean of its divisors is an integer number (177250011598525).

Almost surely, 2354500023197049 is an apocalyptic number.

It is an amenable number.

354500023197049 is a deficient number, since it is larger than the sum of its proper divisors (1).

354500023197049 is an equidigital number, since it uses as much as digits as its factorization.

354500023197049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4082400, while the sum is 52.

The spelling of 354500023197049 in words is "three hundred fifty-four trillion, five hundred billion, twenty-three million, one hundred ninety-seven thousand, forty-nine".