Search a number
-
+
3550200334041 = 35657946122111
BaseRepresentation
bin110011101010011000011…
…011100000011011011001
3110120101200120021011221210
4303222120123200123121
5431131302241142131
611314534534053333
7514331162634444
oct63523033403331
913511616234853
103550200334041
1111496a4598149
12494076aaa249
131c9a23090a3a
14c3b8b2b865b
15625375e0146
hex33a986e06d9

3550200334041 has 16 divisors (see below), whose sum is σ = 4735151774208. Its totient is φ = 2366024707200.

The previous prime is 3550200334033. The next prime is 3550200334069. The reversal of 3550200334041 is 1404330020553.

3550200334041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 3550200334041 - 23 = 3550200334033 is a prime.

It is not an unprimeable number, because it can be changed into a prime (3550200334741) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 160551576 + ... + 160573686.

It is an arithmetic number, because the mean of its divisors is an integer number (295946985888).

Almost surely, 23550200334041 is an apocalyptic number.

It is an amenable number.

3550200334041 is a deficient number, since it is larger than the sum of its proper divisors (1184951440167).

3550200334041 is a wasteful number, since it uses less digits than its factorization.

3550200334041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37232.

The product of its (nonzero) digits is 21600, while the sum is 30.

Adding to 3550200334041 its reverse (1404330020553), we get a palindrome (4954530354594).

The spelling of 3550200334041 in words is "three trillion, five hundred fifty billion, two hundred million, three hundred thirty-four thousand, forty-one".

Divisors: 1 3 5657 9461 16971 22111 28383 66333 53520877 125081927 160562631 209192171 375245781 627576513 1183400111347 3550200334041