Base | Representation |
---|---|
bin | 110011101010100110001… |
… | …000110011001011011010 |
3 | 110120102021121000020012202 |
4 | 303222212020303023122 |
5 | 431132240124424010 |
6 | 11315013431210202 |
7 | 514336654463543 |
oct | 63524610631332 |
9 | 13512247006182 |
10 | 3550430311130 |
11 | 114980239535a |
12 | 49411bb16962 |
13 | 1c9a5b912761 |
14 | c3bada614ca |
15 | 6254c8bb6a5 |
hex | 33aa62332da |
3550430311130 has 16 divisors (see below), whose sum is σ = 6393469994784. Its totient is φ = 1419573138960.
The previous prime is 3550430311121. The next prime is 3550430311139. The reversal of 3550430311130 is 311130340553.
3550430311130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (3550430311121) and next prime (3550430311139).
It is a junction number, because it is equal to n+sod(n) for n = 3550430311093 and 3550430311102.
It is not an unprimeable number, because it can be changed into a prime (3550430311139) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 74848292 + ... + 74895711.
It is an arithmetic number, because the mean of its divisors is an integer number (399591874674).
Almost surely, 23550430311130 is an apocalyptic number.
3550430311130 is a deficient number, since it is larger than the sum of its proper divisors (2843039683654).
3550430311130 is a wasteful number, since it uses less digits than its factorization.
3550430311130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 149746381.
The product of its (nonzero) digits is 8100, while the sum is 29.
Adding to 3550430311130 its reverse (311130340553), we get a palindrome (3861560651683).
The spelling of 3550430311130 in words is "three trillion, five hundred fifty billion, four hundred thirty million, three hundred eleven thousand, one hundred thirty".
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