Base | Representation |
---|---|
bin | 1010010101011001011… |
… | …10111011010110011011 |
3 | 1020221112111122021002220 |
4 | 11022230232323112123 |
5 | 21304203314114042 |
6 | 431042434155123 |
7 | 34440226155063 |
oct | 5125456732633 |
9 | 1227474567086 |
10 | 355085301147 |
11 | 127655439375 |
12 | 58999422aa3 |
13 | 2763b2c5465 |
14 | 13286dba3a3 |
15 | 93837098ec |
hex | 52acbbb59b |
355085301147 has 16 divisors (see below), whose sum is σ = 486262321440. Its totient is φ = 230316417792.
The previous prime is 355085301107. The next prime is 355085301149. The reversal of 355085301147 is 741103580553.
It is not a de Polignac number, because 355085301147 - 215 = 355085268379 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 355085301099 and 355085301108.
It is not an unprimeable number, because it can be changed into a prime (355085301149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3762129 + ... + 3855357.
It is an arithmetic number, because the mean of its divisors is an integer number (30391395090).
Almost surely, 2355085301147 is an apocalyptic number.
355085301147 is a gapful number since it is divisible by the number (37) formed by its first and last digit.
355085301147 is a deficient number, since it is larger than the sum of its proper divisors (131177020293).
355085301147 is a wasteful number, since it uses less digits than its factorization.
355085301147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 127582.
The product of its (nonzero) digits is 252000, while the sum is 42.
The spelling of 355085301147 in words is "three hundred fifty-five billion, eighty-five million, three hundred one thousand, one hundred forty-seven".
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