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355125067441 is a prime number
BaseRepresentation
bin1010010101011110001…
…10100111111010110001
31020221122021110121012121
411022233012213322301
521304244004124231
6431050414354241
734441221160564
oct5125706477261
91227567417177
10355125067441
1112767592a381
12589aa7bb981
1327646609801
141328c3ac4db
159386e62311
hex52af1a7eb1

355125067441 has 2 divisors, whose sum is σ = 355125067442. Its totient is φ = 355125067440.

The previous prime is 355125067421. The next prime is 355125067483. The reversal of 355125067441 is 144760521553.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 326835173025 + 28289894416 = 571695^2 + 168196^2 .

It is an emirp because it is prime and its reverse (144760521553) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 355125067441 - 213 = 355125059249 is a prime.

It is a super-2 number, since 2×3551250674412 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (355125067411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177562533720 + 177562533721.

It is an arithmetic number, because the mean of its divisors is an integer number (177562533721).

Almost surely, 2355125067441 is an apocalyptic number.

It is an amenable number.

355125067441 is a deficient number, since it is larger than the sum of its proper divisors (1).

355125067441 is an equidigital number, since it uses as much as digits as its factorization.

355125067441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504000, while the sum is 43.

Adding to 355125067441 its reverse (144760521553), we get a palindrome (499885588994).

The spelling of 355125067441 in words is "three hundred fifty-five billion, one hundred twenty-five million, sixty-seven thousand, four hundred forty-one".