Base | Representation |
---|---|
bin | 10000001001111010100100… |
… | …00111000111010111101001 |
3 | 11122210011100221222020121221 |
4 | 20010331102013013113221 |
5 | 14124020301314231441 |
6 | 203315552244302041 |
7 | 10324412623363441 |
oct | 1004752207072751 |
9 | 148704327866557 |
10 | 35525052102121 |
11 | 103570a985913a |
12 | 3b98bb00a1921 |
13 | 16a8cc88ca93a |
14 | 8ab5c91c3121 |
15 | 41914c6938d1 |
hex | 204f521c75e9 |
35525052102121 has 2 divisors, whose sum is σ = 35525052102122. Its totient is φ = 35525052102120.
The previous prime is 35525052102103. The next prime is 35525052102157. The reversal of 35525052102121 is 12120125052553.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 21462094598400 + 14062957503721 = 4632720^2 + 3750061^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-35525052102121 is a prime.
It is not a weakly prime, because it can be changed into another prime (35525052102191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17762526051060 + 17762526051061.
It is an arithmetic number, because the mean of its divisors is an integer number (17762526051061).
Almost surely, 235525052102121 is an apocalyptic number.
It is an amenable number.
35525052102121 is a deficient number, since it is larger than the sum of its proper divisors (1).
35525052102121 is an equidigital number, since it uses as much as digits as its factorization.
35525052102121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30000, while the sum is 34.
Adding to 35525052102121 its reverse (12120125052553), we get a palindrome (47645177154674).
The spelling of 35525052102121 in words is "thirty-five trillion, five hundred twenty-five billion, fifty-two million, one hundred two thousand, one hundred twenty-one".
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