Base | Representation |
---|---|
bin | 1101001111001101… |
… | …0001101000001001 |
3 | 100011122102011020011 |
4 | 3103303101220021 |
5 | 24234134342441 |
6 | 1344334231521 |
7 | 154025456146 |
oct | 32363215011 |
9 | 10148364204 |
10 | 3553434121 |
11 | 1563903716 |
12 | 8320555a1 |
13 | 448257b53 |
14 | 259d0b3cd |
15 | 15be64581 |
hex | d3cd1a09 |
3553434121 has 2 divisors, whose sum is σ = 3553434122. Its totient is φ = 3553434120.
The previous prime is 3553434103. The next prime is 3553434149. The reversal of 3553434121 is 1214343553.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3452150025 + 101284096 = 58755^2 + 10064^2 .
It is an emirp because it is prime and its reverse (1214343553) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3553434121 - 25 = 3553434089 is a prime.
It is not a weakly prime, because it can be changed into another prime (3557434121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1776717060 + 1776717061.
It is an arithmetic number, because the mean of its divisors is an integer number (1776717061).
Almost surely, 23553434121 is an apocalyptic number.
It is an amenable number.
3553434121 is a deficient number, since it is larger than the sum of its proper divisors (1).
3553434121 is an equidigital number, since it uses as much as digits as its factorization.
3553434121 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 21600, while the sum is 31.
The square root of 3553434121 is about 59610.6879762346. The cubic root of 3553434121 is about 1525.9820418017.
Adding to 3553434121 its reverse (1214343553), we get a palindrome (4767777674).
The spelling of 3553434121 in words is "three billion, five hundred fifty-three million, four hundred thirty-four thousand, one hundred twenty-one".
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