Base | Representation |
---|---|
bin | 110011101110001001110… |
… | …100111101000110100001 |
3 | 110120210010211000111012220 |
4 | 303232021310331012201 |
5 | 431213101040023040 |
6 | 11320444451141253 |
7 | 514533431123556 |
oct | 63561164750641 |
9 | 13523124014186 |
10 | 3554250314145 |
11 | 1150392709143 |
12 | 494a072a4829 |
13 | 1ca21a16177b |
14 | c405311ca2d |
15 | 626c2e392d0 |
hex | 33b89d3d1a1 |
3554250314145 has 16 divisors (see below), whose sum is σ = 5699244278400. Its totient is φ = 1891452242304.
The previous prime is 3554250314143. The next prime is 3554250314149. The reversal of 3554250314145 is 5414130524553.
It is not a de Polignac number, because 3554250314145 - 21 = 3554250314143 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3554250314097 and 3554250314106.
It is not an unprimeable number, because it can be changed into a prime (3554250314143) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 259238245 + ... + 259251954.
It is an arithmetic number, because the mean of its divisors is an integer number (356202767400).
Almost surely, 23554250314145 is an apocalyptic number.
It is an amenable number.
3554250314145 is a deficient number, since it is larger than the sum of its proper divisors (2144993964255).
3554250314145 is a wasteful number, since it uses less digits than its factorization.
3554250314145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 518490664.
The product of its (nonzero) digits is 720000, while the sum is 42.
Adding to 3554250314145 its reverse (5414130524553), we get a palindrome (8968380838698).
The spelling of 3554250314145 in words is "three trillion, five hundred fifty-four billion, two hundred fifty million, three hundred fourteen thousand, one hundred forty-five".
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