Base | Representation |
---|---|
bin | 101000011010001101001101… |
… | …1101010100001111110001001 |
3 | 1201121112021000002110222212221 |
4 | 1100310122123222201332021 |
5 | 333042104403331200131 |
6 | 3255545225420534041 |
7 | 134604043134640132 |
oct | 12064323352417611 |
9 | 1647467002428787 |
10 | 355445515100041 |
11 | a328a661912823 |
12 | 33a4787b9b1321 |
13 | 123444a307c632 |
14 | 63ab9247c0c89 |
15 | 2b15e48374411 |
hex | 143469baa1f89 |
355445515100041 has 2 divisors, whose sum is σ = 355445515100042. Its totient is φ = 355445515100040.
The previous prime is 355445515100003. The next prime is 355445515100057. The reversal of 355445515100041 is 140001515544553.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 179488049209225 + 175957465890816 = 13397315^2 + 13264896^2 .
It is a cyclic number.
It is not a de Polignac number, because 355445515100041 - 245 = 320261143011209 is a prime.
It is not a weakly prime, because it can be changed into another prime (355445515101041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177722757550020 + 177722757550021.
It is an arithmetic number, because the mean of its divisors is an integer number (177722757550021).
Almost surely, 2355445515100041 is an apocalyptic number.
It is an amenable number.
355445515100041 is a deficient number, since it is larger than the sum of its proper divisors (1).
355445515100041 is an equidigital number, since it uses as much as digits as its factorization.
355445515100041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 600000, while the sum is 43.
The spelling of 355445515100041 in words is "three hundred fifty-five trillion, four hundred forty-five billion, five hundred fifteen million, one hundred thousand, forty-one".
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