Base | Representation |
---|---|
bin | 1011000100000100110… |
… | …10101001001001010011 |
3 | 1100100012222011012102201 |
4 | 11202002122221021103 |
5 | 22212014124110103 |
6 | 450345233424031 |
7 | 36315231261433 |
oct | 5420232511123 |
9 | 1310188135381 |
10 | 380145144403 |
11 | 137245029532 |
12 | 61811a0b017 |
13 | 29b0305248b |
14 | 145832a02c3 |
15 | 9d4d79d51d |
hex | 58826a9253 |
380145144403 has 4 divisors (see below), whose sum is σ = 380158954848. Its totient is φ = 380131333960.
The previous prime is 380145144397. The next prime is 380145144443. The reversal of 380145144403 is 304441541083.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 304441541083 = 37 ⋅8228149759.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-380145144403 is a prime.
It is a super-5 number, since 5×3801451444035 (a number of 59 digits) contains 55555 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (380145144443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6863851 + ... + 6919012.
It is an arithmetic number, because the mean of its divisors is an integer number (95039738712).
Almost surely, 2380145144403 is an apocalyptic number.
380145144403 is a deficient number, since it is larger than the sum of its proper divisors (13810445).
380145144403 is a wasteful number, since it uses less digits than its factorization.
380145144403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13810444.
The product of its (nonzero) digits is 92160, while the sum is 37.
Adding to 380145144403 its reverse (304441541083), we get a palindrome (684586685486).
The spelling of 380145144403 in words is "three hundred eighty billion, one hundred forty-five million, one hundred forty-four thousand, four hundred three".
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