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3806812285147 = 29131269389143
BaseRepresentation
bin110111011001010111101…
…100011010100011011011
3111110221001021220221212001
4313121113230122203123
5444332322421111042
612032454142501431
7542014233345544
oct67312754324333
914427037827761
103806812285147
1112385073230a3
12515951894877
13217c99c39c21
14d2371cb34cb
1569055b20bb7
hex37657b1a8db

3806812285147 has 4 divisors (see below), whose sum is σ = 3938081674320. Its totient is φ = 3675542895976.

The previous prime is 3806812285121. The next prime is 3806812285151. The reversal of 3806812285147 is 7415822186083.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3806812285147 - 227 = 3806678067419 is a prime.

It is a super-2 number, since 2×38068122851472 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3806812285247) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 65634694543 + ... + 65634694600.

It is an arithmetic number, because the mean of its divisors is an integer number (984520418580).

Almost surely, 23806812285147 is an apocalyptic number.

3806812285147 is a deficient number, since it is larger than the sum of its proper divisors (131269389173).

3806812285147 is a wasteful number, since it uses less digits than its factorization.

3806812285147 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 131269389172.

The product of its (nonzero) digits is 5160960, while the sum is 55.

The spelling of 3806812285147 in words is "three trillion, eight hundred six billion, eight hundred twelve million, two hundred eighty-five thousand, one hundred forty-seven".

Divisors: 1 29 131269389143 3806812285147