38344074748153 has 2 divisors, whose sum is σ = 38344074748154. Its totient is φ = 38344074748152.

The previous prime is 38344074748061. The next prime is 38344074748159. The reversal of 38344074748153 is 35184747044383.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 37611763262649 + 732311485504 = 6132843^2 + 855752^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-38344074748153 is a prime.

It is a super-2 number, since 2×38344074748153² (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 38344074748091 and 38344074748100.

It is not a weakly prime, because it can be changed into another prime (38344074748159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19172037374076 + 19172037374077.

It is an arithmetic number, because the mean of its divisors is an integer number (19172037374077).

Almost surely, 2^{38344074748153} is an apocalyptic number.

It is an amenable number.

38344074748153 is a deficient number, since it is larger than the sum of its proper divisors (1).

38344074748153 is an equidigital number, since it uses as much as digits as its factorization.

38344074748153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108380160, while the sum is 61.

The spelling of 38344074748153 in words is "thirty-eight trillion, three hundred forty-four billion, seventy-four million, seven hundred forty-eight thousand, one hundred fifty-three".