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38416996913 is a prime number
BaseRepresentation
bin100011110001110101…
…001101101000110001
310200011100100122111112
4203301311031220301
51112134222400123
625352025323105
72530003041311
oct436165155061
9120140318445
1038416996913
1115324436429
127541936495
13381311b049
141c0625d441
15eeca43d78
hex8f1d4da31

38416996913 has 2 divisors, whose sum is σ = 38416996914. Its totient is φ = 38416996912.

The previous prime is 38416996901. The next prime is 38416996931. The reversal of 38416996913 is 31969961483.

38416996913 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (38416996931) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 27140256049 + 11276740864 = 164743^2 + 106192^2 .

It is an emirp because it is prime and its reverse (31969961483) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 38416996913 - 210 = 38416995889 is a prime.

It is not a weakly prime, because it can be changed into another prime (38416996963) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19208498456 + 19208498457.

It is an arithmetic number, because the mean of its divisors is an integer number (19208498457).

Almost surely, 238416996913 is an apocalyptic number.

It is an amenable number.

38416996913 is a deficient number, since it is larger than the sum of its proper divisors (1).

38416996913 is an equidigital number, since it uses as much as digits as its factorization.

38416996913 is an evil number, because the sum of its binary digits is even.

The product of its digits is 7558272, while the sum is 59.

The spelling of 38416996913 in words is "thirty-eight billion, four hundred sixteen million, nine hundred ninety-six thousand, nine hundred thirteen".