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384799914713 is a prime number
BaseRepresentation
bin1011001100101111101…
…11001011101011011001
31100210020100221000220002
411212113313023223121
522301032234232323
6452435153342345
736541462210364
oct5462767135331
91323210830802
10384799914713
1113921357a345
12626b08679b5
132a395508236
14148a55770db
15a02225e828
hex5997dcbad9

384799914713 has 2 divisors, whose sum is σ = 384799914714. Its totient is φ = 384799914712.

The previous prime is 384799914701. The next prime is 384799914743. The reversal of 384799914713 is 317419997483.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 228037766089 + 156762148624 = 477533^2 + 395932^2 .

It is a cyclic number.

It is not a de Polignac number, because 384799914713 - 236 = 316080437977 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 384799914713.

It is not a weakly prime, because it can be changed into another prime (384799914743) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 192399957356 + 192399957357.

It is an arithmetic number, because the mean of its divisors is an integer number (192399957357).

Almost surely, 2384799914713 is an apocalyptic number.

It is an amenable number.

384799914713 is a deficient number, since it is larger than the sum of its proper divisors (1).

384799914713 is an equidigital number, since it uses as much as digits as its factorization.

384799914713 is an evil number, because the sum of its binary digits is even.

The product of its digits is 41150592, while the sum is 65.

The spelling of 384799914713 in words is "three hundred eighty-four billion, seven hundred ninety-nine million, nine hundred fourteen thousand, seven hundred thirteen".