Base | Representation |
---|---|
bin | 111000001000110000101… |
… | …110010011011001010001 |
3 | 111122210101121111222102110 |
4 | 320020300232103121101 |
5 | 1001201031201414431 |
6 | 12112111345535533 |
7 | 545465232420612 |
oct | 70106056233121 |
9 | 14583347458373 |
10 | 3857698076241 |
11 | 1258049aa30a9 |
12 | 5237933445a9 |
13 | 21ca19369a99 |
14 | d49dc101c09 |
15 | 6a533137346 |
hex | 38230b93651 |
3857698076241 has 4 divisors (see below), whose sum is σ = 5143597434992. Its totient is φ = 2571798717492.
The previous prime is 3857698076227. The next prime is 3857698076341. The reversal of 3857698076241 is 1426708967583.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 3857698076241 - 215 = 3857698043473 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3857698076341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 642949679371 + ... + 642949679376.
It is an arithmetic number, because the mean of its divisors is an integer number (1285899358748).
It is a 1-persistent number, because it is pandigital, but 2⋅3857698076241 = 7715396152482 is not.
Almost surely, 23857698076241 is an apocalyptic number.
It is an amenable number.
3857698076241 is a deficient number, since it is larger than the sum of its proper divisors (1285899358751).
3857698076241 is a wasteful number, since it uses less digits than its factorization.
3857698076241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1285899358750.
The product of its (nonzero) digits is 121927680, while the sum is 66.
The spelling of 3857698076241 in words is "three trillion, eight hundred fifty-seven billion, six hundred ninety-eight million, seventy-six thousand, two hundred forty-one".
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