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3886151738113 = 15592492720807
BaseRepresentation
bin111000100011010000101…
…100011010001100000001
3111202111211121002202200001
4320203100230122030001
51002132314321104423
612133135022400001
7550523314515211
oct70432054321401
914674747082601
103886151738113
111269120387437
125291b4430001
132226022671b8
14d613b024241
156b14b111cad
hex388d0b1a301

3886151738113 has 4 divisors (see below), whose sum is σ = 3888644460480. Its totient is φ = 3883659015748.

The previous prime is 3886151738111. The next prime is 3886151738129. The reversal of 3886151738113 is 3118371516883.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3886151738113 - 21 = 3886151738111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3886151738111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1246358845 + ... + 1246361962.

It is an arithmetic number, because the mean of its divisors is an integer number (972161115120).

Almost surely, 23886151738113 is an apocalyptic number.

It is an amenable number.

3886151738113 is a deficient number, since it is larger than the sum of its proper divisors (2492722367).

3886151738113 is a wasteful number, since it uses less digits than its factorization.

3886151738113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2492722366.

The product of its digits is 2903040, while the sum is 55.

It can be divided in two parts, 3886151 and 738113, that added together give a palindrome (4624264).

The spelling of 3886151738113 in words is "three trillion, eight hundred eighty-six billion, one hundred fifty-one million, seven hundred thirty-eight thousand, one hundred thirteen".

Divisors: 1 1559 2492720807 3886151738113