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38913243011 = 207711873441
BaseRepresentation
bin100100001111011010…
…001111011110000011
310201102221010120011122
4210033122033132003
51114143242234021
625513153502455
72545210052036
oct441732173603
9121387116148
1038913243011
1115559569475
12765bb71a2b
133891b8a5a6
141c5211901d
15102b3b9bab
hex90f68f783

38913243011 has 4 divisors (see below), whose sum is σ = 38915137224. Its totient is φ = 38911348800.

The previous prime is 38913242971. The next prime is 38913243041. The reversal of 38913243011 is 11034231983.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 38913243011 - 210 = 38913241987 is a prime.

It is a super-2 number, since 2×389132430112 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (38913243041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 915950 + ... + 957491.

It is an arithmetic number, because the mean of its divisors is an integer number (9728784306).

Almost surely, 238913243011 is an apocalyptic number.

38913243011 is a deficient number, since it is larger than the sum of its proper divisors (1894213).

38913243011 is a wasteful number, since it uses less digits than its factorization.

38913243011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1894212.

The product of its (nonzero) digits is 15552, while the sum is 35.

Adding to 38913243011 its reverse (11034231983), we get a palindrome (49947474994).

The spelling of 38913243011 in words is "thirty-eight billion, nine hundred thirteen million, two hundred forty-three thousand, eleven".

Divisors: 1 20771 1873441 38913243011