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3893354101441 = 7556193443063
BaseRepresentation
bin111000101001111101111…
…111001111101011000001
3111210012102112121201202101
4320221331333033223001
51002242042122221231
612140325430150401
7551166641554060
oct70517577175301
914705375551671
103893354101441
111271186988622
1252a6844b2401
132231ac47404c
14d66217ba1d7
156b41d5a0661
hex38a7dfcfac1

3893354101441 has 4 divisors (see below), whose sum is σ = 4449547544512. Its totient is φ = 3337160658372.

The previous prime is 3893354101393. The next prime is 3893354101501. The reversal of 3893354101441 is 1441014533983.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3893354101441 - 217 = 3893353970369 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3893354101391 and 3893354101400.

It is not an unprimeable number, because it can be changed into a prime (3893354105441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 278096721525 + ... + 278096721538.

It is an arithmetic number, because the mean of its divisors is an integer number (1112386886128).

Almost surely, 23893354101441 is an apocalyptic number.

It is an amenable number.

3893354101441 is a deficient number, since it is larger than the sum of its proper divisors (556193443071).

3893354101441 is an equidigital number, since it uses as much as digits as its factorization.

3893354101441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 556193443070.

The product of its (nonzero) digits is 622080, while the sum is 46.

The spelling of 3893354101441 in words is "three trillion, eight hundred ninety-three billion, three hundred fifty-four million, one hundred one thousand, four hundred forty-one".

Divisors: 1 7 556193443063 3893354101441