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39140329857 = 313046776619
BaseRepresentation
bin100100011100111100…
…100000100110000001
310202000202102202202120
4210130330200212001
51120124411023412
625551505034453
72553635212566
oct443474404601
9122022382676
1039140329857
1115665772152
127704025a29
1338c9c398c5
141c7434c86d
1510412c4b8c
hex91cf20981

39140329857 has 4 divisors (see below), whose sum is σ = 52187106480. Its totient is φ = 26093553236.

The previous prime is 39140329841. The next prime is 39140329889. The reversal of 39140329857 is 75892304193.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 39140329857 - 24 = 39140329841 is a prime.

It is a super-3 number, since 3×391403298573 (a number of 33 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (39140329057) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6523388307 + ... + 6523388312.

It is an arithmetic number, because the mean of its divisors is an integer number (13046776620).

Almost surely, 239140329857 is an apocalyptic number.

It is an amenable number.

39140329857 is a deficient number, since it is larger than the sum of its proper divisors (13046776623).

39140329857 is a wasteful number, since it uses less digits than its factorization.

39140329857 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13046776622.

The product of its (nonzero) digits is 1632960, while the sum is 51.

The spelling of 39140329857 in words is "thirty-nine billion, one hundred forty million, three hundred twenty-nine thousand, eight hundred fifty-seven".

Divisors: 1 3 13046776619 39140329857