Base | Representation |
---|---|
bin | 100100011101111101… |
… | …110010110101110001 |
3 | 10202001221122020212222 |
4 | 210131331302311301 |
5 | 1120143301201303 |
6 | 25553315530425 |
7 | 2554233532115 |
oct | 443575626561 |
9 | 122057566788 |
10 | 39157443953 |
11 | 156743a1231 |
12 | 77098b9a15 |
13 | 390064c5a4 |
14 | 1c76725745 |
15 | 1042a55938 |
hex | 91df72d71 |
39157443953 has 4 divisors (see below), whose sum is σ = 39212673780. Its totient is φ = 39102214128.
The previous prime is 39157443917. The next prime is 39157443959. The reversal of 39157443953 is 35934475193.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 22317969664 + 16839474289 = 149392^2 + 129767^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-39157443953 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 39157443895 and 39157443904.
It is not an unprimeable number, because it can be changed into a prime (39157443959) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27613850 + ... + 27615267.
It is an arithmetic number, because the mean of its divisors is an integer number (9803168445).
Almost surely, 239157443953 is an apocalyptic number.
It is an amenable number.
39157443953 is a deficient number, since it is larger than the sum of its proper divisors (55229827).
39157443953 is an equidigital number, since it uses as much as digits as its factorization.
39157443953 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 55229826.
The product of its digits is 6123600, while the sum is 53.
The spelling of 39157443953 in words is "thirty-nine billion, one hundred fifty-seven million, four hundred forty-three thousand, nine hundred fifty-three".
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