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393130433 is a prime number
BaseRepresentation
bin10111011011101…
…011000111000001
31000101202002120102
4113123223013001
51301120133213
6103002052145
712512360603
oct2733530701
91011662512
10393130433
11191a03793
12ab7aa055
13635a7877
143a2d7173
15247a8158
hex176eb1c1

393130433 has 2 divisors, whose sum is σ = 393130434. Its totient is φ = 393130432.

The previous prime is 393130429. The next prime is 393130447. The reversal of 393130433 is 334031393.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 338118544 + 55011889 = 18388^2 + 7417^2 .

It is an emirp because it is prime and its reverse (334031393) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 393130433 - 22 = 393130429 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 393130396 and 393130405.

It is not a weakly prime, because it can be changed into another prime (393130453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 196565216 + 196565217.

It is an arithmetic number, because the mean of its divisors is an integer number (196565217).

Almost surely, 2393130433 is an apocalyptic number.

It is an amenable number.

393130433 is a deficient number, since it is larger than the sum of its proper divisors (1).

393130433 is an equidigital number, since it uses as much as digits as its factorization.

393130433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8748, while the sum is 29.

The square root of 393130433 is about 19827.5170659364. The cubic root of 393130433 is about 732.5639702312.

The spelling of 393130433 in words is "three hundred ninety-three million, one hundred thirty thousand, four hundred thirty-three".