Search a number
-
+
39325441 = 62712
BaseRepresentation
bin1001011000000…
…0111100000001
32201222221100211
42112000330001
540031403231
63522514121
7655155301
oct226007401
981887324
1039325441
112021a871
1211205941
1381bb7bc
145319601
1536bbeb1
hex2580f01

39325441 has 3 divisors (see below), whose sum is σ = 39331713. Its totient is φ = 39319170.

The previous prime is 39325411. The next prime is 39325513. The reversal of 39325441 is 14452393.

The square root of 39325441 is 6271.

It is a perfect power (a square), and thus also a powerful number.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 14452393 = 101143093.

It is not a de Polignac number, because 39325441 - 27 = 39325313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (39325411) by changing a digit.

It is a polite number, since it can be written in 2 ways as a sum of consecutive naturals, for example, 3136 + ... + 9406.

It is an arithmetic number, because the mean of its divisors is an integer number (13110571).

Almost surely, 239325441 is an apocalyptic number.

39325441 is the 6271-st square number.

39325441 is the 3136-th centered octagonal number.

It is an amenable number.

39325441 is a deficient number, since it is larger than the sum of its proper divisors (6272).

39325441 is an frugal number, since it uses more digits than its factorization.

39325441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12542 (or 6271 counting only the distinct ones).

The product of its digits is 12960, while the sum is 31.

The cubic root of 39325441 is about 340.0618140207.

The spelling of 39325441 in words is "thirty-nine million, three hundred twenty-five thousand, four hundred forty-one".

Divisors: 1 6271 39325441