Base | Representation |
---|---|
bin | 111001010001001100100… |
… | …010110101001100101011 |
3 | 111221020010222002120211010 |
4 | 321101030202311030223 |
5 | 1003434322401223342 |
6 | 12211533143035003 |
7 | 554220502055514 |
oct | 71211442651453 |
9 | 14836128076733 |
10 | 3935474242347 |
11 | 128803068092a |
12 | 53687a43ba63 |
13 | 227162846a4b |
14 | d8699797a0b |
15 | 6c58627c29c |
hex | 3944c8b532b |
3935474242347 has 8 divisors (see below), whose sum is σ = 5248249781760. Its totient is φ = 2623174098920.
The previous prime is 3935474242327. The next prime is 3935474242369. The reversal of 3935474242347 is 7432424745393.
3935474242347 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 3935474242347 - 222 = 3935470048043 is a prime.
It is not an unprimeable number, because it can be changed into a prime (3935474242327) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 118829679 + ... + 118862792.
It is an arithmetic number, because the mean of its divisors is an integer number (656031222720).
Almost surely, 23935474242347 is an apocalyptic number.
3935474242347 is a deficient number, since it is larger than the sum of its proper divisors (1312775539413).
3935474242347 is a wasteful number, since it uses less digits than its factorization.
3935474242347 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 237697993.
The product of its digits is 60963840, while the sum is 57.
The spelling of 3935474242347 in words is "three trillion, nine hundred thirty-five billion, four hundred seventy-four million, two hundred forty-two thousand, three hundred forty-seven".
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