Base | Representation |
---|---|
bin | 100100101100101010… |
… | …001101110111001001 |
3 | 10202201010112002001001 |
4 | 210230222031313021 |
5 | 1121144404014433 |
6 | 30034003455001 |
7 | 2563316134663 |
oct | 445452156711 |
9 | 122633462031 |
10 | 39403969993 |
11 | 15790571963 |
12 | 7778387461 |
13 | 393c74699b |
14 | 1c9b379533 |
15 | 105950057d |
hex | 92ca8ddc9 |
39403969993 has 2 divisors, whose sum is σ = 39403969994. Its totient is φ = 39403969992.
The previous prime is 39403969951. The next prime is 39403970051. The reversal of 39403969993 is 39996930493.
39403969993 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 24910940224 + 14493029769 = 157832^2 + 120387^2 .
It is a cyclic number.
It is not a de Polignac number, because 39403969993 - 213 = 39403961801 is a prime.
It is not a weakly prime, because it can be changed into another prime (39403969093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19701984996 + 19701984997.
It is an arithmetic number, because the mean of its divisors is an integer number (19701984997).
Almost surely, 239403969993 is an apocalyptic number.
It is an amenable number.
39403969993 is a deficient number, since it is larger than the sum of its proper divisors (1).
39403969993 is an equidigital number, since it uses as much as digits as its factorization.
39403969993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38263752, while the sum is 64.
The spelling of 39403969993 in words is "thirty-nine billion, four hundred three million, nine hundred sixty-nine thousand, nine hundred ninety-three".
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