Base | Representation |
---|---|
bin | 1011011110001001011… |
… | …01010101001010011001 |
3 | 1101200100110011101212211 |
4 | 11233010231111022121 |
5 | 22424200403211213 |
6 | 501022204035121 |
7 | 40322132526463 |
oct | 5570455251231 |
9 | 1350313141784 |
10 | 394142241433 |
11 | 142178024716 |
12 | 64479532aa1 |
13 | 2b223b85c05 |
14 | 1511021d133 |
15 | a3bc50b53d |
hex | 5bc4b55299 |
394142241433 has 2 divisors, whose sum is σ = 394142241434. Its totient is φ = 394142241432.
The previous prime is 394142241419. The next prime is 394142241527. The reversal of 394142241433 is 334142241493.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 361108451929 + 33033789504 = 600923^2 + 181752^2 .
It is an emirp because it is prime and its reverse (334142241493) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 394142241433 - 217 = 394142110361 is a prime.
It is not a weakly prime, because it can be changed into another prime (394142241403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 197071120716 + 197071120717.
It is an arithmetic number, because the mean of its divisors is an integer number (197071120717).
Almost surely, 2394142241433 is an apocalyptic number.
It is an amenable number.
394142241433 is a deficient number, since it is larger than the sum of its proper divisors (1).
394142241433 is an equidigital number, since it uses as much as digits as its factorization.
394142241433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 248832, while the sum is 40.
The spelling of 394142241433 in words is "three hundred ninety-four billion, one hundred forty-two million, two hundred forty-one thousand, four hundred thirty-three".
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