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397041448051 is a prime number
BaseRepresentation
bin1011100011100011000…
…00111011010001110011
31101221211111112100200201
411301301200323101303
523001120102314201
6502222012100031
740454025424063
oct5616140732163
91357744470621
10397041448051
11143425601546
1264b48464617
132b5967097a1
14153072a93a3
15a4dbce0801
hex5c7183b473

397041448051 has 2 divisors, whose sum is σ = 397041448052. Its totient is φ = 397041448050.

The previous prime is 397041448043. The next prime is 397041448103. The reversal of 397041448051 is 150844140793.

It is a weak prime.

It is an emirp because it is prime and its reverse (150844140793) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 397041448051 - 23 = 397041448043 is a prime.

It is a super-2 number, since 2×3970414480512 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 397041447992 and 397041448010.

It is not a weakly prime, because it can be changed into another prime (397041448651) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 198520724025 + 198520724026.

It is an arithmetic number, because the mean of its divisors is an integer number (198520724026).

Almost surely, 2397041448051 is an apocalyptic number.

397041448051 is a deficient number, since it is larger than the sum of its proper divisors (1).

397041448051 is an equidigital number, since it uses as much as digits as its factorization.

397041448051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 483840, while the sum is 46.

The spelling of 397041448051 in words is "three hundred ninety-seven billion, forty-one million, four hundred forty-eight thousand, fifty-one".