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397242613152019 is a prime number
BaseRepresentation
bin101101001010010100100000…
…0110110001011100100010011
31221002112000121201102221100201
41122110221000312023210103
5404031410332431331034
63524510423121200031
7146446555162302115
oct13224510066134423
91832460551387321
10397242613152019
11105634712037a28
1238678343490017
1314086a825b898b
1470149060a73b5
1530dd2d2e73014
hex1694a40d8b913

397242613152019 has 2 divisors, whose sum is σ = 397242613152020. Its totient is φ = 397242613152018.

The previous prime is 397242613151963. The next prime is 397242613152037. The reversal of 397242613152019 is 910251316242793.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 397242613152019 - 217 = 397242613020947 is a prime.

It is a super-2 number, since 2×3972426131520192 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (397242613159019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 198621306576009 + 198621306576010.

It is an arithmetic number, because the mean of its divisors is an integer number (198621306576010).

Almost surely, 2397242613152019 is an apocalyptic number.

397242613152019 is a deficient number, since it is larger than the sum of its proper divisors (1).

397242613152019 is an equidigital number, since it uses as much as digits as its factorization.

397242613152019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4898880, while the sum is 55.

The spelling of 397242613152019 in words is "three hundred ninety-seven trillion, two hundred forty-two billion, six hundred thirteen million, one hundred fifty-two thousand, nineteen".