Base | Representation |
---|---|
bin | 101101001010010100100000… |
… | …0110110001011100100010011 |
3 | 1221002112000121201102221100201 |
4 | 1122110221000312023210103 |
5 | 404031410332431331034 |
6 | 3524510423121200031 |
7 | 146446555162302115 |
oct | 13224510066134423 |
9 | 1832460551387321 |
10 | 397242613152019 |
11 | 105634712037a28 |
12 | 38678343490017 |
13 | 14086a825b898b |
14 | 70149060a73b5 |
15 | 30dd2d2e73014 |
hex | 1694a40d8b913 |
397242613152019 has 2 divisors, whose sum is σ = 397242613152020. Its totient is φ = 397242613152018.
The previous prime is 397242613151963. The next prime is 397242613152037. The reversal of 397242613152019 is 910251316242793.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 397242613152019 - 217 = 397242613020947 is a prime.
It is a super-2 number, since 2×3972426131520192 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (397242613159019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 198621306576009 + 198621306576010.
It is an arithmetic number, because the mean of its divisors is an integer number (198621306576010).
Almost surely, 2397242613152019 is an apocalyptic number.
397242613152019 is a deficient number, since it is larger than the sum of its proper divisors (1).
397242613152019 is an equidigital number, since it uses as much as digits as its factorization.
397242613152019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4898880, while the sum is 55.
The spelling of 397242613152019 in words is "three hundred ninety-seven trillion, two hundred forty-two billion, six hundred thirteen million, one hundred fifty-two thousand, nineteen".
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