| Base | Representation |
|---|---|
| bin | 100101000101000011… |
| … | …000000000000000000 |
| 3 | 10210202122102001100000 |
| 4 | 211011003000000000 |
| 5 | 1123014124320000 |
| 6 | 30142341200000 |
| 7 | 2606414636103 |
| oct | 450503000000 |
| 9 | 123678361300 |
| 10 | 39813120000 |
| 11 | 15980517365 |
| 12 | 7871400000 |
| 13 | 39a643cc94 |
| 14 | 1cd984273a |
| 15 | 10803c0000 |
| hex | 9450c0000 |
39813120000 has 570 divisors, whose sum is σ = 149046405508. Its totient is φ = 10616832000.
The previous prime is 39813119939. The next prime is 39813120013. The reversal of 39813120000 is 2131893.
It is a powerful number, because all its prime factors have an exponent greater than 1 and also an Achilles number because it is not a perfect power.
It is a Jordan-Polya number, since it can be written as 6! ⋅ (5!)3 ⋅ (2!)5.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (7) of ones.
It is a polite number, since it can be written in 29 ways as a sum of consecutive naturals, for example, 7962623998 + ... + 7962624002.
Almost surely, 239813120000 is an apocalyptic number.
39813120000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 39813120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (74523202754).
39813120000 is an abundant number, since it is smaller than the sum of its proper divisors (109233285508).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
39813120000 is an frugal number, since it uses more digits than its factorization.
39813120000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71 (or 10 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 27.
Multiplying 39813120000 by its sum of digits (27), we get a square (1074954240000 = 10368002).
39813120000 divided by its sum of digits (27) gives a square (1474560000 = 384002).
Adding to 39813120000 its reverse (2131893), we get a palindrome (39815251893).
The spelling of 39813120000 in words is "thirty-nine billion, eight hundred thirteen million, one hundred twenty thousand".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •