3981355603 has 4 divisors (see below), whose sum is σ = 3981484728. Its totient is φ = 3981226480.

The previous prime is 3981355583. The next prime is 3981355607. The reversal of 3981355603 is 3065531893.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3065531893 = 431 ⋅7112603.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3981355603 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 3981355603.

It is not an unprimeable number, because it can be changed into a prime (3981355607) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11775 + ... + 90007.

It is an arithmetic number, because the mean of its divisors is an integer number (995371182).

Almost surely, 2^3981355603 is an apocalyptic number.

3981355603 is a deficient number, since it is larger than the sum of its proper divisors (129125).

3981355603 is an equidigital number, since it uses as much as digits as its factorization.

3981355603 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 129124.

The product of its (nonzero) digits is 291600, while the sum is 43.

The square root of 3981355603 is about 63097.9841437110. The cubic root of 3981355603 is about 1584.9308654378.

The spelling of 3981355603 in words is "three billion, nine hundred eighty-one million, three hundred fifty-five thousand, six hundred three".