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399312000001 = 1225332588917
BaseRepresentation
bin1011100111110001101…
…10011001010000000001
31102011200201222100102101
411303320312121100001
523020242333000001
6503235201550401
740564215666055
oct5637066312001
91364621870371
10399312000001
11144390239862
1265480945401
132b868c40c55
1415480a6dc65
15a5c12e6a01
hex5cf8d99401

399312000001 has 4 divisors (see below), whose sum is σ = 399344601172. Its totient is φ = 399279398832.

The previous prime is 399311999963. The next prime is 399312000053. The reversal of 399312000001 is 100000213993.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 317195366401 + 82116633600 = 563201^2 + 286560^2 .

It is a cyclic number.

It is not a de Polignac number, because 399312000001 - 217 = 399311868929 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (399312060001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16282206 + ... + 16306711.

It is an arithmetic number, because the mean of its divisors is an integer number (99836150293).

Almost surely, 2399312000001 is an apocalyptic number.

It is an amenable number.

399312000001 is a deficient number, since it is larger than the sum of its proper divisors (32601171).

399312000001 is a wasteful number, since it uses less digits than its factorization.

399312000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32601170.

The product of its (nonzero) digits is 1458, while the sum is 28.

Adding to 399312000001 its reverse (100000213993), we get a palindrome (499312213994).

The spelling of 399312000001 in words is "three hundred ninety-nine billion, three hundred twelve million, one", and thus it is an aban number.

Divisors: 1 12253 32588917 399312000001