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39947114857081 is a prime number
BaseRepresentation
bin10010001010100111010011…
…00101110100001001111001
312020102220111010012101122111
421011103221211310021321
520213443142400411311
6220543241244052321
711262040513536415
oct1105235145641171
9166386433171574
1039947114857081
1111801526a10493
124592027b340a1
131939cc5b895a3
149c164491dd45
154941b1e1ed21
hex2454e9974279

39947114857081 has 2 divisors, whose sum is σ = 39947114857082. Its totient is φ = 39947114857080.

The previous prime is 39947114857033. The next prime is 39947114857187. The reversal of 39947114857081 is 18075841174993.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 30569188581481 + 9377926275600 = 5528941^2 + 3062340^2 .

It is a cyclic number.

It is not a de Polignac number, because 39947114857081 - 215 = 39947114824313 is a prime.

It is a super-2 number, since 2×399471148570812 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 39947114856998 and 39947114857016.

It is not a weakly prime, because it can be changed into another prime (39947114858081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19973557428540 + 19973557428541.

It is an arithmetic number, because the mean of its divisors is an integer number (19973557428541).

Almost surely, 239947114857081 is an apocalyptic number.

It is an amenable number.

39947114857081 is a deficient number, since it is larger than the sum of its proper divisors (1).

39947114857081 is an equidigital number, since it uses as much as digits as its factorization.

39947114857081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60963840, while the sum is 67.

The spelling of 39947114857081 in words is "thirty-nine trillion, nine hundred forty-seven billion, one hundred fourteen million, eight hundred fifty-seven thousand, eighty-one".