Base | Representation |
---|---|
bin | 100101001111110101… |
… | …111010110000000011 |
3 | 10211020021012220021021 |
4 | 211033311322300003 |
5 | 1123402011140003 |
6 | 30212331210311 |
7 | 2614044300544 |
oct | 451765726003 |
9 | 124207186237 |
10 | 39994240003 |
11 | 15a63784513 |
12 | 7901ba6997 |
13 | 3a04b16893 |
14 | 1d1590c4cb |
15 | 109124a2bd |
hex | 94fd7ac03 |
39994240003 has 2 divisors, whose sum is σ = 39994240004. Its totient is φ = 39994240002.
The previous prime is 39994239991. The next prime is 39994240007. The reversal of 39994240003 is 30004249993.
It is a strong prime.
It is an emirp because it is prime and its reverse (30004249993) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-39994240003 is a prime.
It is not a weakly prime, because it can be changed into another prime (39994240007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19997120001 + 19997120002.
It is an arithmetic number, because the mean of its divisors is an integer number (19997120002).
Almost surely, 239994240003 is an apocalyptic number.
39994240003 is a deficient number, since it is larger than the sum of its proper divisors (1).
39994240003 is an equidigital number, since it uses as much as digits as its factorization.
39994240003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 209952, while the sum is 43.
Adding to 39994240003 its reverse (30004249993), we get a palindrome (69998489996).
The spelling of 39994240003 in words is "thirty-nine billion, nine hundred ninety-four million, two hundred forty thousand, three".
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