Search a number
-
+
400010000111993 is a prime number
BaseRepresentation
bin101101011110011101001010…
…1111101101001100101111001
31221110022120201200020102220002
41122330322111331221211321
5404412230440012040433
63534430020204042345
7150153524462321645
oct13274722575514571
91843276650212802
10400010000111993
11106501319907867
1238a4474b8333b5
1314227a2027719b
1470ac8317d9c25
15313a2a100e9e8
hex16bce95f69979

400010000111993 has 2 divisors, whose sum is σ = 400010000111994. Its totient is φ = 400010000111992.

The previous prime is 400010000111957. The next prime is 400010000112053. The reversal of 400010000111993 is 399111000010004.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 231220976226304 + 168789023885689 = 15205952^2 + 12991883^2 .

It is a cyclic number.

It is not a de Polignac number, because 400010000111993 - 224 = 400009983334777 is a prime.

It is not a weakly prime, because it can be changed into another prime (400010000111903) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200005000055996 + 200005000055997.

It is an arithmetic number, because the mean of its divisors is an integer number (200005000055997).

Almost surely, 2400010000111993 is an apocalyptic number.

It is an amenable number.

400010000111993 is a deficient number, since it is larger than the sum of its proper divisors (1).

400010000111993 is an equidigital number, since it uses as much as digits as its factorization.

400010000111993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 29.

Adding to 400010000111993 its reverse (399111000010004), we get a palindrome (799121000121997).

The spelling of 400010000111993 in words is "four hundred trillion, ten billion, one hundred eleven thousand, nine hundred ninety-three".