Base | Representation |
---|---|
bin | 101101011110011101001010… |
… | …1111101101001100101111001 |
3 | 1221110022120201200020102220002 |
4 | 1122330322111331221211321 |
5 | 404412230440012040433 |
6 | 3534430020204042345 |
7 | 150153524462321645 |
oct | 13274722575514571 |
9 | 1843276650212802 |
10 | 400010000111993 |
11 | 106501319907867 |
12 | 38a4474b8333b5 |
13 | 14227a2027719b |
14 | 70ac8317d9c25 |
15 | 313a2a100e9e8 |
hex | 16bce95f69979 |
400010000111993 has 2 divisors, whose sum is σ = 400010000111994. Its totient is φ = 400010000111992.
The previous prime is 400010000111957. The next prime is 400010000112053. The reversal of 400010000111993 is 399111000010004.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 231220976226304 + 168789023885689 = 15205952^2 + 12991883^2 .
It is a cyclic number.
It is not a de Polignac number, because 400010000111993 - 224 = 400009983334777 is a prime.
It is not a weakly prime, because it can be changed into another prime (400010000111903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200005000055996 + 200005000055997.
It is an arithmetic number, because the mean of its divisors is an integer number (200005000055997).
Almost surely, 2400010000111993 is an apocalyptic number.
It is an amenable number.
400010000111993 is a deficient number, since it is larger than the sum of its proper divisors (1).
400010000111993 is an equidigital number, since it uses as much as digits as its factorization.
400010000111993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 29.
Adding to 400010000111993 its reverse (399111000010004), we get a palindrome (799121000121997).
The spelling of 400010000111993 in words is "four hundred trillion, ten billion, one hundred eleven thousand, nine hundred ninety-three".
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