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40001335041 = 313333778347
BaseRepresentation
bin100101010000010000…
…111110111100000001
310211020202120100211110
4211100100332330001
51123410320210131
630213143233533
72614161511023
oct452020767401
9124222510743
1040001335041
1115a67790088
1279044488a9
133a0642c125
141d16838013
151091b9c646
hex95043ef01

40001335041 has 4 divisors (see below), whose sum is σ = 53335113392. Its totient is φ = 26667556692.

The previous prime is 40001335021. The next prime is 40001335043. The reversal of 40001335041 is 14053310004.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 40001335041 - 210 = 40001334017 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 40001334999 and 40001335017.

It is not an unprimeable number, because it can be changed into a prime (40001335043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6666889171 + ... + 6666889176.

It is an arithmetic number, because the mean of its divisors is an integer number (13333778348).

Almost surely, 240001335041 is an apocalyptic number.

It is an amenable number.

40001335041 is a deficient number, since it is larger than the sum of its proper divisors (13333778351).

40001335041 is a wasteful number, since it uses less digits than its factorization.

40001335041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13333778350.

The product of its (nonzero) digits is 720, while the sum is 21.

Adding to 40001335041 its reverse (14053310004), we get a palindrome (54054645045).

The spelling of 40001335041 in words is "forty billion, one million, three hundred thirty-five thousand, forty-one".

Divisors: 1 3 13333778347 40001335041