Base | Representation |
---|---|
bin | 101101011110011110111000… |
… | …0010100000101000111101011 |
3 | 1221110022221011222102000121201 |
4 | 1122330331300110011013223 |
5 | 404412310440314100003 |
6 | 3534431423505345031 |
7 | 150154014324056545 |
oct | 13274756024050753 |
9 | 1843287158360551 |
10 | 400013663425003 |
11 | 10650292973a081 |
12 | 38a453b2638177 |
13 | 142281851c4214 |
14 | 70aca9c14a695 |
15 | 313a41792ab1d |
hex | 16bcf705051eb |
400013663425003 has 4 divisors (see below), whose sum is σ = 400014175068760. Its totient is φ = 400013151781248.
The previous prime is 400013663424959. The next prime is 400013663425067. The reversal of 400013663425003 is 300524366310004.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 400013663425003 - 29 = 400013663424491 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (400013661425003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 254647350 + ... + 256213387.
It is an arithmetic number, because the mean of its divisors is an integer number (100003543767190).
Almost surely, 2400013663425003 is an apocalyptic number.
400013663425003 is a deficient number, since it is larger than the sum of its proper divisors (511643757).
400013663425003 is an equidigital number, since it uses as much as digits as its factorization.
400013663425003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 511643756.
The product of its (nonzero) digits is 155520, while the sum is 37.
The spelling of 400013663425003 in words is "four hundred trillion, thirteen billion, six hundred sixty-three million, four hundred twenty-five thousand, three".
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